Monday, 11 January 2016

Solution of LIGHT OJ 1241 :: Pinocchio


Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
#include <math.h>
int main()
{
    int tst, i, j;
    double a;
    scanf("%d", &tst);
    for(i=1; i<=tst; i++)
    {
        int n, cnt=0;
        scanf("%d", &n);
        int ara[n];
        for(j=0; j<n; j++)
            scanf("%d", &ara[j]);
        a = ara[0]-2;
        cnt = ceil(a/5.0);
        for(j=1; j<n; j++)
        {
            a = ara[j]-ara[j-1];
            cnt += ceil(a/5.0);
        }
        printf("Case %d: %d\n", i, cnt);
    }
    return 0;
}

0 comments:

Post a Comment

Note: only a member of this blog may post a comment.