Tuesday, 12 January 2016

Solution of URI 1012 :: Area

   , ,  1 comment

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    double A,B,C,D,E,F,G,H;
    scanf ("%lf %lf %lf", &A, &B, &C);
    D=.5*A*C;
    E=3.14159*C*C;
    F=.5*(A+B)*C;
    G=B*B;
    H=A*B;
    printf ("TRIANGULO: %.3lf\n", D);
    printf ("CIRCULO: %.3lf\n", E);
    printf ("TRAPEZIO: %.3lf\n", F);
    printf ("QUADRADO: %.3lf\n", G);
    printf ("RETANGULO: %.3lf\n", H);
    return 0;
}

1 comment:

  1. Unknown19 September 2020 at 18:45

    #include
    int main()
    {
    double A, B, C, pi=3.14159,RTA, CA, TRAPI, SA, RA;

    scanf("%lf%lf%lf",&A,&B,&C);
    RTA = (1/2.0)*A*C;
    CA= pi*C*C;
    TRAPI= ((A+B)/2.0)*C;
    SA= B*B;
    RA= A*B;
    printf("TRIANGULO: %.3lf\n",RTA);
    printf("CIRCULO: %.3lf\n",CA);
    printf("TRAPIZIO: %.3lf\n",TRAPI);
    printf("QUADRADO: %.3lf\n",SA);
    printf("RETANGULO: %.3lf\n",RA);
    return 0;
    }
    /* what is different between your code and my code. please give the solution of problem and explanation*/

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