Solution of URI 1020 :: Age in Days

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/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int a,b,c,d, N;
    scanf ("%d", &N);
    a=N/365;
    b=N%365;
    c=b/30;
    d=b%30;
    printf ("%d ano(s)\n%d mes(es)\n%d dia(s)\n",a,c,d);
    return 0;
}