Thursday, 28 January 2016

Solution of URI 1049 :: Animal


Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
#include <string.h>
int main()
{
    char c1[]="vertebrado", c11[22]="ave", c12[]="mamifero";
    char c111[]="carnivoro", c112[]="onivoro", c124[]="herbivoro";
    char a1[]="aguia", a2[]="pomba", a3[]="homem", a4[]="vaca";
    char c2[]="invertebrado", c21[]="inseto", c22[]="anelideo";
    char c211[]="hematofago", a5[]="pulga", a6[]="lagarta";
    char a7[]="sanguessuga", a8[]="minhoca";
    char a[22], b[22], c[22];
    scanf("%s", a);
    if(0==strcmp(a,c1))
    {
        scanf("%s",b);
        if(0==strcmp(b,c11))
        {
            scanf("%s",c);
            if(0==strcmp(c,c111))
                printf("%s\n",a1);
            else if(0==strcmp(c,c112))
                printf("%s\n",a2);
        }
        if(0==strcmp(b,c12))
        {
            scanf("%s",&c);
            if(0==strcmp(c,c112))
                printf("%s\n",a3);
            else if(0==strcmp(c,c124))
                printf("%s\n",a4);
        }
    }
    else if(0==strcmp(a,c2))
    {
        scanf("%s",b);
        if(0==strcmp(b,c21))
        {
            scanf("%s",&c);
            if(0==strcmp(c,c211))
                printf("%s\n",a5);
            else if(0==strcmp(c,c124))
                printf("%s\n",a6);
        }
        if(0==strcmp(b,c22))
        {
            scanf("%s",&c);
            if(0==strcmp(c,c211))
                printf("%s\n",a7);
            else if(0==strcmp(c,c112))
                printf("%s\n",a8);
        }
    }
    return 0;
}

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