Solution of URI 1050 :: DDD

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
   int N;
    scanf("%d",&N);
    if(N==61)
        printf("Brasilia\n");
    else if(N==71)
        printf("Salvador\n");
    else if(N==11)
        printf("Sao Paulo\n");
    else if(N==21)
        printf("Rio de Janeiro\n");
    else if(N==32)
        printf("Juiz de Fora\n");
    else if(N==19)
        printf("Campinas\n");
    else if(N==27)
        printf("Vitoria\n");
    else if(N==31)
        printf("Bela Horizonte\n");
    else
        printf("DDD nao cadastrado\n");
    return 0;
}