Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
int main()
{
int a,b,c,d,e,f,q,r;
scanf("%d%d", &a, &b);
if(a<0)
{
e=b;
if(b<0) e=b*-1;
for(r=0; r<e; r++)
{
f=a-r;
if(f%b==0) break;
}
q=f/b;
}
else
{
q=a/b;
r=a%b;
}
printf("%d %d\n",q,r);
return 0;
}
Couldn't understand the logic, can you explain please.
ReplyDeleteyeah, I don't know why the answer is different if the first number is negative :/ to my mind, a division between 7 and 3 is never going to result a quotient of -3, that's crazy :s
DeleteFabriccio. This is because the rest can't be negative. The rest must be always positive, so when dividend is negative, you have to multiply once more to make rest being positive. The math's life.
Deletei've printed the output they wanted!! then, where is the wrong of 5%!!
Delete#include
int main()
{
int a,b,c,d;
scanf("%d %d",&a,&b);
c=a/b;
if(a<0) d=(a%b)*(-1);
else d=a%b;
printf("%d %d\n",c,d);
return 0;
}
why 10% wrong?i am so tried for this problem.
ReplyDeleteplease describe me..
#include
using namespace std;
int main()
{
int a,b,p,r;
scanf("%d %d",&a,&b);
p=a/b;
r=a-(b*p);
r=a%b;
if(r<0){
if(p>0)p++;
if(p<0)p--;
r=a-(b*p);
}
printf("%d %d\n",p,r);
}
if we solve like that where is the problem??!!
ReplyDelete#include
int main()
{
int a,b,c,d;
scanf("%d %d",&a,&b);
c=a/b;
if(a<0) d=(a%b)*(-1);
else d=a%b;
printf("%d %d\n",c,d);
return 0;
}
Not good...
ReplyDelete#include
ReplyDeleteint main()
{
int a,b,c,d;
scanf("%d %d",&a,&b);
c=a/b;
if(a<0)
d=(a%b)*(-1);
else
d=a%b;
printf("%d %d\n",c,d);
return 0;
}
why it is 5 % wrong .......
#include
ReplyDelete#include
int main()
{
int a,b,x,y,i;
scanf("%d%d",&a,&b);
if(a<0&&b>0)
{
i=a/b-1;
y=a-(i*b);
printf("%d %d\n",i,y);
}
else if(a<0&&b<0)
{
x=a;
b=abs(b);
a=abs(a);
for(i=1;;i++)
{
if(b*i>=a)
{
y=(b*i)+x;
printf("%d %d\n",i,y);
break;
}
}
}
else
{
i=a/b;
y=a%b;
printf("%d %d\n",i,y);
}
return 0;
}
Why this code is 5% wrong?
#include
ReplyDeleteint main ()
{
int e,f,a,b;
scanf ("%d%d",&a,&b);
if (a>0&&b>0&&b!=0)
{
e=a/b;
f=a -b*e;
}
else if (a>0&&b<0&&b!=0)
{
e=(a/b);
f=a - (e*b);
}
else if (a<0&&b>0&&b!=0)
{
e = (a/b)-1;
f= a-b*e;
}
else
{
e= a/b;
f= a - b*e;
}
printf ("%d %d\n",e,f);
return 0;
}
why this is showing 5% wrong answer??
#include
ReplyDeleteint main ()
{
int a,b,c,e,f;
scanf ("%d%d",&a,&b);
if (a>=0&&b>0)
{
e=a/b;
f=a -b*e;
}
else if (a>=0&&b<0)
{
e=(a/b);
f=a-(b*e);
}
else if (a<0&&b>0)
{
c=a*(-1);
if (c==b)
{
e=a/b;
f=a-e*b;
}
else
{
e = (a/b)-1;
f= a-b*e;
}
}
else if (a<0&&b<0)
{
if (a==b)
{
e=(a/b);
f=a-e*b;
}
else
{
e= (a/b)+1;
f= a - b*e;
}
}
printf ("%d %d\n",e,f);
return 0;
}
why this is showing me 5% wrong