Friday, 15 January 2016

Solution of URI 1848 :: Counting Crow

do you feel your code Beginner, C, URI 6 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
#include <string.h>
int main()
{
    int a,b,c,d,e,f,i,sum=0;
    char ara[10];
    for(i=1; i<=3; i++)
    {
        sum=0;
        while(1)
        {
            gets(ara);
            if(ara[0]=='c') break;

            if(ara[0]=='-')
            {
                if(ara[1]=='-')
                {
                    if(ara[2]=='-') sum+=0;
                    else sum+=1;
                }
                else
                {
                    if(ara[2]=='-') sum+=2;
                    else sum+=3;
                }
            }
            else if(ara[0]=='*')
            {
                if(ara[1]=='-')
                {
                    if(ara[2]=='-')sum+=4;
                    else sum+=5;
                }
                else
                {
                    if(ara[2]=='-') sum+=6;
                    else sum+=7;
                }
            }
        }
        printf("%d\n", sum);
    }
    return 0;
}

6 comments:

Unknown11 January 2017 at 02:09
why you are adding numbers 2,3,4,5,6,7 with the 'sum'?
shoudn't it be just 1 or 0?
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Unknown9 May 2018 at 09:15
i didnt use that much 'if', code below

#include
#include

int main (){

char entrada[10]; //used to get the inputs
char pisca [10] = {"caw caw"}; // string used to compare when to sum
int valores [3]; // values of the 3 numbers
int soma = 0;
int i;

for (i=0; i <=2;i++) // // clear the values (just as a good coding practice)
valores[i]=0;

i = 0;

do{
gets (entrada);

if(strcmp(pisca,entrada) == 0){ //
valores [i] = soma; // sum the current numbers
i++; // moves to the next number
soma = 0; // clean the sum
}

if(entrada[0]== '*') // last bit = 2^2
soma +=4;

if(entrada[1]== '*') // second bit = 2^1
soma +=2;

if(entrada[2]== '*')// first bit = 2^0
soma +=1;

}while ( i<=2);

for (i=0;i<=2;i++)
printf("%d\n",valores[i]); // shows the 3 values

return 0;
}
accepted

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IT Bazar10 October 2018 at 19:35
Here is My Code [Accepted]

#include

int main()
{
char s[50];
int sum=0,i;
for(i=0;i<3;i++){
sum=0;
while(1)
{
gets(s);
if(s[0]=='*')sum+=4;
if(s[1]=='*')sum+=2;
if(s[2]=='*') sum+=1;

if(s[0]>='c'&&s[6]=='w') break;
}
printf("%d\n",sum);
}
return 0;
}

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