Friday 4 March 2016

Solution of URI 1071 :: Sum of Consecutive Odd Numbers I

   , ,  3 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int a,b,c=0;
    scanf("%d %d", &a, &b);
    if(a==b)
        printf("%d\n",c);
    else if(a<b)
    {
        for(a=a+1;a<b;a++)
        {
            if(a%2==1||a%2==-1)
                c+=a;
        }
        printf("%d\n",c);
    }
    else if(a>b)
    {
        for(b=b+1;b<a;b++)
        {
            if(b%2==1||b%2==-1)
                c+=b;
        }
        printf("%d\n",c);
    }
    return 0;
}

3 comments:

  1. Edo6 May 2016 at 21:39

    I was tried to create a sorted list with value between from the input given, it's give the same answer. But my code still rated with Wrong Answer.

    ReplyDelete
    Replies
    1. Edo6 May 2016 at 21:46

      with absolute value off course, to prevent minus value ruin everything.

      Delete
  2. Anonymous3 May 2018 at 18:43

    #include

    int main()
    {
    int X, Y, temp, sum = 0;

    scanf("%d %d", &X, &Y);

    if (Y < X){
    temp = X;
    X = Y;
    Y = temp;
    }
    if (X %2 == 0)
    X++;
    else
    X+=2;

    while(X < Y)
    {
    sum = sum + X;
    X+=2;
    }
    printf("%d\n", sum);

    return 0;
    }

    ReplyDelete

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