Friday, 4 March 2016

Solution of URI 1074 :: Even or Odd

do you feel your code Beginner, C, URI 4 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int N,X,a;
    scanf ("%d", &N);
    for(a=1;a<=N;a++)
    {
        scanf ("%d",&X);
        if(X==0)
            printf("NULL\n");
        else if(X<=0&&X%2==0)
            printf ("EVEN NEGATIVE\n");
        else if(X<=0&&X%2==-1)
            printf ("ODD NEGATIVE\n");
        else if(X>=0&&X%2==0)
            printf ("EVEN POSITIVE\n");
        else if(X>=0&&X%2==1)
            printf ("ODD POSITIVE\n");
    }
    return 0;
}

4 comments:

Arafat Rahman15 May 2017 at 13:27
This comment has been removed by the author.
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Arafat Rahman15 May 2017 at 13:29
#include
int main()
{
int a,b,c;
scanf("%d",&c);

for(b=1;b<=c;b++){
scanf("%d",&a);
if(a==0)
{
printf("NULL\n");
}

else if (a>0&&a%2==0){
printf("EVEN POSITIVE\n");
}
else if (a>0&&a%2==1){
printf("ODD POSITIVE\n");
}
else if (a<0&&a%2==0){
printf("EVEN NEGETIVE\n");
}
else if (a<0&&a%2==-1){
printf("ODD NEGETIVE\n");
}

}

return 0;
}
whats wrong
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Anonymous19 March 2018 at 23:18
#include
int main()
{
int i,j,k[100];
scanf("%d",&j);
for(i=0; i0)
printf("EVEN POSITIVE\n");
else
printf("EVEN NEGATIVE\n");
}
else if(k[i]%2!=0)
{
if(k[i]>0)
printf("ODD POSITIVE\n");
else
printf("ODD NEGATIVE\n");
}
}
}
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