Monday, 7 March 2016

Solution of URI 1094 :: Experiments

do you feel your code Beginner, C, URI 7 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int a,b,c,d=0,e=0,f=0,g;
    double x,y,z;
    char m[2],n[2],p[2],q[2];
    scanf("%d", &a);
    for(b=1; b<=a; b++)
    {
        scanf("%d%s",&c,&m);
        if(m[0]=='C') d+=c;
        else if(m[0]=='R') e+=c;
        else if(m[0]=='S') f+=c;
    }
    g=d+e+f;
    x=(d/(g*1.0))*100.00;
    y=(e/(g*1.0))*100.00;
    z=(f/(g*1.0))*100.00;
    printf("Total: %d cobaias\n",g);
    printf("Total de coelhos: %d\n",d);
    printf("Total de ratos: %d\n",e);
    printf("Total de sapos: %d\n",f);
    printf("Percentual de coelhos: %.2lf %%\n",x);
    printf("Percentual de ratos: %.2lf %%\n",y);
    printf("Percentual de sapos: %.2lf %%\n",z);
    return 0;
}

7 comments:

Musafir5 April 2018 at 17:32
why you multiple 1.0 with the total?
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Unknown7 July 2018 at 03:13
#include
int main ()
{

float i,b,c,d=0,f,g,h;
char a;
scanf("%f",&b);
for(i=1;i<=b;i++){
scanf("%f %c",&c,&a);
d+=c;
if(a=='C'){
f+=c;
}
if(a=='R'){
g+=c;
}
if(a=='S'){
h+=c;
}
}

float l=((f/d)*100);
float k=((g/d)*100);
float m=((h/d)*100);

printf("Total: %.0f cobaias\n",d);
printf("Total de coelhos: %.0f\n",f);
printf("Total de ratos: %.0f\n",g);
printf("Total de sapos: %.0f\n",h);
printf("Percentual de coelhos: %.2f %\n",l);
printf("Percentual de ratos: %.2f %\n",k);
printf("Percentual de sapos: %.2f %\n",m);
}
please tell me why its having 30% eror ?
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Unknown8 October 2018 at 18:05
can you please tell me where is wrong??
it shows 5% error
#include
main()
{
int i,n,s=0,c=0,r=0,t,a;
double cp,rp,sp;
char ch[2];
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%d%s",&a,&ch);
if(ch[0]=='C')
{
c+=a;
}
else if(ch[0]=='R')
{
r+=a;
}
else if(ch[0]=='S')
{
s+=a;
}
}
t=r+c+s;
rp=(r/(t*1.0))*100.00;
cp=(c/(t*1.0))*100.00;
sp=(s/(t*1.0))*100.00;
printf("Total: %d\n",t);
printf("Total de coelhos: %d\n",c);
printf("Total de ratos: %d\n",r);
printf("Total de sapos: %d\n",s);
printf("Percentual de coelhos: %.2lf %\n",cp);
printf("Percentual de ratos: %.2lf %\n",rp);
printf("Percentual de sapos: %.2lf %\n",sp);
return 0;
}
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Unknown16 October 2018 at 22:44
#include
int main()
{
char name;
int a[15],i,n;
int C=0,R=0,S=0;
float c,r,s,total;

scanf("%d",&n);

/**
scanf("%d", &n);
for(i=1; i<=a; i++)
{
scanf("%d%s",&a[i],&name);
if(name[0]=='C') C+=a[i];
else if(name[0]=='R') R+=a[i];
else if(name[0]=='S') S+=a[i];
}

*/

for(i=0 ; i<n ; i++)
{
scanf("%d",&a[i]);
scanf(" %c",&name);
if(name=='C')
{
C+=a[i];
}
else if(name=='R')
{
R+=a[i];
}
else if(name=='S')
{
S+=a[i];
}

}

total=C+R+S;

c=(C/(total*1.0))*100;
r=(R/(total*1.0))*100;
s=(S/(total*1.0))*100;

printf("Total: %.0f cobaias\n",total);
printf("Total de coelhos: %d\n",C);
printf("Total de ratos: %d\n",R);
printf("Total de sapos: %d\n",S);

printf("Percentual de coelhos: %.2f %c\n",c,'%');
printf("Percentual de ratos: %.2f %c\n",r,'%');
printf("Percentual de sapos: %.2f %c\n",s,'%');

return 0;
}

i face runtime error. what happen. plz help me :(
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Anonymous9 May 2019 at 02:17
i don't know what is wrong in my code, can someone help me?

#include

int main()
{
char a;
int b=0,cc=0,rr=0,ss=0,tot=0,x=0,y=0;
float med1,med2,med3;
scanf("%i",&x);
do{
scanf("%i %c\n",&b,&a);
tot=tot+b;
if (a=='C')
cc=cc+b;
else if (a=='R')
rr=rr+b;
else if (a=='S')
ss=ss+b;
y++;
}while (y!=x);
printf("Total: %i cobaias\n",tot);
printf("Total de coelhos: %i\n",cc);
printf("Total de ratos: %i\n",rr);
printf("Total de sapos: %i\n",ss);
med1=(100*cc)/tot;
printf("Percentual de coelhos: %.2f %\n",med1);
med2=(100*rr)/tot;
printf("Percentual de ratos: %.2f %\n",med2);
med3=(100*ss)/tot;
printf("Percentual de sapos: %.2f %\n",med3);
return 0;
}
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