Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
int main()
{
double a,b=1,c, S=0;
for(a=1; a<=39; a+=2)
{
c=a/b;
S+=c;
b*=2;
}
printf("%.2lf\n",S);
return 0;
}
#include
ReplyDelete#include
int main()
{
double i,z=0.0;
for(i=0;i<=19;i++)
{
z = z + ((2.0i+1)/pow(2.0,i));
}
printf("%.2lf",z);
return 0;
}
what's wrong in this code?
This comment has been removed by the author.
ReplyDelete#include
ReplyDeleteint main()
{
int i,n,j,sum=0;
scanf("%d",&n);
while(n!=0)
{
if(n%2==0)
n=n;
else
n=n+1;
for(j=1;j<=5;j++)
{
sum+=n;
n=n+2;
}
printf("%d\n",sum);
n=0;
sum=0;
scanf("%d",&n);
}
return 0;
}
reply...
#include
ReplyDelete#include
int main()
{
int i,x,j=2,count=0;
float sum=1;
for(i=3;i<=39;i=i+2)
{
count++;
x=pow(j,count);
sum=sum+(i/(float)x);
}
printf("%.2f\n",sum);
return 0;
}
reply..