Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/ #include <stdio.h> #include <math.h> int main() { double A, B, C, X1, X2, D; printf("Please, Input A, B and C.\n"); scanf("%lf %lf %lf", &A, &B, &C); D = (B*B) - (4*A*C); if(D<0) printf("There is no Solution\n"); else if(D==0) { X1 = (-B/(2*A)); printf("X = %.2lf\n", X1); } else { X1 = (-B + sqrt(D))/(2*A); X2 = (-B - sqrt(D))/(2*A); printf("X1 = %.2lf\n", X1); printf("X2 = %.2lf\n", X2); } return 0; }
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