Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
#include <math.h>
int main()
{
double A, B, C, X1, X2, D;
printf("Please, Input A, B and C.\n");
scanf("%lf %lf %lf", &A, &B, &C);
D = (B*B) - (4*A*C);
if(D<0)
printf("There is no Solution\n");
else if(D==0)
{
X1 = (-B/(2*A));
printf("X = %.2lf\n", X1);
}
else
{
X1 = (-B + sqrt(D))/(2*A);
X2 = (-B - sqrt(D))/(2*A);
printf("X1 = %.2lf\n", X1);
printf("X2 = %.2lf\n", X2);
}
return 0;
}
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