Monday 11 January 2016

Solution of LIGHT OJ 1354 :: IP Checking


Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
#include <string.h>
int main()
{
    int tst, i, j, k, dgt,cnt;
    char dcml[50], bnry[50];
    scanf("%d", &tst);
    for(i=1; i<=tst; i++)
    {
        int ara1[4], ara2[4];
        for(k=0; k<4; k++)
            ara1[k]=ara2[k]=0;
        scanf("%s", dcml);
        scanf("%s", bnry);
        for(j=0, k=0; dcml[j]; j++)
        {
            if(dcml[j]=='.') k++;
            else
            {
            dgt = dcml[j]-48;
            ara1[k] = ara1[k]*10 + dgt;
            }
        }
        for(j=0, k=0; bnry[j]; j++)
        {
            if(bnry[j]=='.') k++;
            else
            {
            dgt = bnry[j]-48;
            ara2[k] = ara2[k]*2 + dgt;
            }
        }
        for(j=0, cnt=0; j<4; j++)
        {
            if(ara1[j]==ara2[j])
                cnt++;
        }
        if(cnt==4) printf("Case %d: Yes\n", i);
        else printf("Case %d: No\n", i);

    }
    return 0;
}

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