Solution of LIGHT OJ 1387 :: Setu

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
#include <string.h>
int main()
{
    int tst, n, i, j, k, l, amnt=0, dnate, dgt;
    char str[20];
    scanf("%d", &tst);
    for(i=1; i<=tst; i++)
    {
        scanf("%d", &n);
        getchar();
        printf("Case %d:\n", i);
        for(j=1,amnt=0; j<=n; j++)
        {
            gets(str);
            if(str[0]=='r')
            {
                printf("%d\n", amnt);

            }
            else
            {
                for(k=7, dnate=0; str[k]; k++)
                {
                    dgt = str[k]-48;
                    dnate = dnate*10 + dgt;
                }
                amnt += dnate;
            }
        }
    }
    return 0;
}