Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
int main()
{
char M[100];
scanf ("%s", M);
double a,b,c;
scanf("%lf %lf", &a,&b);
c=a+(b*15)/100;
printf ("TOTAL = R$ %.2lf\n",c);
return 0;
}
>
0 comments:
Post a Comment
Note: only a member of this blog may post a comment.