Friday, 25 March 2016

Solution of LIGHT OJ 1001 :: Opposite Task

   , ,  6 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int a,b,c,d,e;
    scanf("%d", &a);
    for(b=0; b<a; b++)
    {
        scanf ("%d", &c);
        if(c>10)
        {
            d=c-10;
            e=10;
            printf("%d %d\n",d,e);
        }
        else
        {
            d=0;
            printf("%d %d\n",d,c);
        }
    }
    return 0;
}

6 comments:

  1. Lubaba Afzal18 March 2018 at 15:53

    I don't understand this code

    ReplyDelete
  2. Unknown7 July 2018 at 03:23

    problem,, Your code will produce a duplicate result

    ReplyDelete
  3. Sahid hasan30 March 2019 at 22:41

    your code will generate duplicate answer.



    ReplyDelete
  4. The Stupid Blogger24 June 2020 at 12:16

    Yeah felt that ❤

    ReplyDelete
  5. Unknown22 November 2020 at 23:51

    #include

    #include
    int main()
    {
    int tc,n,num,a,b;
    scanf("%d",&n);
    for(tc=1;tc<=n;tc++){
    scanf("%d",&num);
    label1:
    int a =rand()%100;
    int b =rand()%100;
    while((a+b)!=num)
    goto label1;

    printf("Case %d: %d %d",tc,a,b);
    }
    return 0;
    }



    What is the problem in my code ??

    ReplyDelete
  6. Unknown22 November 2020 at 23:53

    #include

    #include
    int main()
    {
    int tc,n,num,a,b;
    scanf("%d",&n);
    for(tc=1;tc<=n;tc++){
    scanf("%d",&num);
    label1:
    int a =rand()%100;
    int b =rand()%100;
    while((a+b)!=num)
    goto label1;

    printf("Case %d: %d %d",tc,a,b);
    }
    return 0;
    }



    What is the problem in my code ??

    ReplyDelete

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