Solution of LIGHT OJ 1116 :: Ekka Dokka

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
#include <math.h>
int main()
{
    long long int m, n, w;
    long long int tst, i, j, odd, Valid, limit;
    scanf("%lld", &tst);
    for(i=1; i<=tst; i++)
    {
        scanf("%lld", &w);
        limit = w/2;
        Valid = 0;
        odd = 0;
        for(j=2; j <= limit;  j *= 2)
        {
            if(w%j == 0)
                odd = w/j;
            if(odd%2 == 1)
            {
                Valid = 1;
                break;
            }
        }
        if(Valid==1)
            printf("Case %lld: %lld %lld\n", i, odd, j);
        else
            printf("Case %lld: Impossible\n", i);
    }
    return 0;
}