Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
int main()
{
int N,X,Y,A,b,c=0;
scanf("%d", &N);
for(A=1;A<=N;A++)
{
scanf("%d%d",&X,&Y);
if(X==Y)
{
c=0;
printf("%d\n",c);
}
else if(X<Y)
{
for(b=X+1,c=0;b<Y;b++)
{
if(b%2==1||b%2==-1)
c+=b;
}
printf("%d\n",c);
}
else
{
for(b=Y+1,c=0;b<X;b++)
{
if(b%2==1||b%2==-1)
c+=b;
}
printf("%d\n",c);
}
}
return 0;
}
vai sob kisu ki input dekhe dekhe likhle hobe logic die koren jeno sob input ei kaj kore
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteBy JAVA
ReplyDeleteint test;
Scanner sc=new Scanner(System.in);
test=sc.nextInt();
int j;
for(j=1;j<=test;j++)
{
int first,sec,i,counta=0;
first=sc.nextInt();
sec=sc.nextInt();
if(first==sec)
{
counta=0;
}
else if(first<sec)
{
if(first%2!=0)
{
for(i=first+2;i<sec;i=i+2)
{
counta=counta+i;
}
}
else{
for(i=first+1;i<sec;i=i+2)
{
counta=counta+i;
}
}
}
else
{
if(sec%2!=0)
{
for(i=sec+2;i<first;i=i+2)
{
counta=counta+i;
}
}
else{
for(i=sec+1;i<first;i=i+2)
{
counta=counta+i;
}
}
}
System.out.println(counta);
}
Nesse codigom a variavel b seria pra que ??
ReplyDeletePlease ask in English..
Deleteshort
Delete#include
int main()
{
int n,x,y,i,j,temp,sum=0;
scanf("%d",&n);
for(i=0;iy)
{
temp=y;
y=x;
x=temp;
}
for(j=x+1;j<y;j++)
{
if(j%2!=0)
{
sum=sum+j;
}
}
printf("%d\n",sum);
sum=0;
}
return 0;
}
#include
ReplyDeleteusing namespace std;
int main()
{
int n,x,y,sum;
cin>>n;
while(n--)
{
cin>>x>>y;
if(x==y)
cout<<"0\n";
else if(x<y)
{
sum=0;
for(int i=x+1; i<y; i++)
{
if(i%2!=0)
sum=sum+i;
}
cout<<sum<<endl;
}
else
{
sum=0;
for(int i=y+1; i<x; i++)
{
if(i%2!=0)
sum=sum+i;
}
cout<<sum<<endl;
}
}
}