Friday, 18 March 2016

Solution of URI 1118 :: Several Scores with Validation

do you feel your code Beginner, C, URI 11 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    double a,b,c,d,e,f,g,h=1,x=1,y=1,z=1;
    for(h=1;;h=1,x=1,y=1,z=1)
    {
        scanf("%lf",&a);
        if(a<0 || a>10)
        {
            printf("nota invalida\n");
            continue;
        }
        while(x==1)
        {
            scanf("%lf",&b);
            if(b<0 || b>10)
            {
                printf("nota invalida\n");
                continue;
            }
            x+=2;
        }
        c=(a+b)/2.0;
        printf("media = %.2lf\n",c);
        printf("novo calculo (1-sim 2-nao)\n");
        while(y==1)
        {
            scanf("%lf", &g);
            if(g<1 || g>2)
            {
                printf("novo calculo (1-sim 2-nao)\n");
                continue;
            }
            y+=2;
        }
        if(g==2)
            break;
    }
    return 0;
}

11 comments:

Anonymous6 February 2017 at 04:58
why did you use the variables x,y and z ? And i don't understand this increment, can you explain too?
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Unknown6 February 2017 at 16:10
parleto expain korbo,,,,easy code gulare etto boro korce
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Unknown9 April 2018 at 23:56
This comment has been removed by the author.
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Unknown9 April 2018 at 23:58

why my code is shown wrong........everything is looking clear and acceptable........but it is showing wrong..

#include
int main()
{
int i,X=0;
double a,c=0;
for(i=0;;i++)
{
scanf("%lf",&a);
if(a>=0&&a<=10)
{
c=c+a;
X++;
}
else
{
printf("nota invalida\n");
}
if(X==2)
{
printf("media = %.2lf\n",c/2);
X=0;
{
c=0;
break;
}

}

}
for(i=0;;i++)
{
printf("novo calculo (1-sim 2-nao)\n");
scanf("%lf",&a);
if(a==1)
{

for(i=0;;i++)
{
scanf("%lf",&a);
if(a>=0&&a<=10)
{
c=c+a;
X++;
}
else
{
printf("nota invalida\n");
}
if(X==2)
{
printf("media = %.2lf\n",c/2);
X=0;
break;
}
}

}
else if(a==2)
break;
}

return 0;
}
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Replies
Faisal Mahmud2 May 2019 at 17:56
note: goto statement make your code inefficient. :)
#include
int main()
{
float x,sum=0.0;
int y=0,t,l;
l:
while(1)
{
if(y==2)
{
printf("media = %.2f\n",sum/2.00);
printf("novo calculo (1-sim 2-nao)\n");
while(scanf("%d",&t)==1)
{
if(t<1 || t>2)
{
printf("novo calculo (1-sim 2-nao)\n");
continue;
}
if(t==1)
{
y=0;
sum=0;
goto l;
}
else
goto m;
}
m:
break;
}
scanf("%f",&x);
if(x>=0.0 && x<=10.0)
{
y++;
sum=sum+x;
}
else
printf("nota invalida\n");
}
return 0;
}
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Replies
Shahid Fahad15 August 2019 at 18:24
its more simple

#include
int main()
{
float score,sum=0,count=0,com;
while(1)
{
if(count==2)
break;
scanf("%f",&score);
if(score>=0&&score<=10)
{
count++;
sum = sum + score;
}
else
printf("nota invalida\n");
}
printf("media = %.2f\n",sum/2);

while(1)
{
printf("novo calculo (1-sim 2-nao)\n");
scanf("%f",&com);
if(com==2)
break;
if(com!=1&&com!=2)
continue;
if(com==1)
{
float score,sum=0,count=0,com;
while(1)
{
if(count==2)
break;
scanf("%f",&score);
if(score>=0&&score<=10)
{
count++;
sum = sum + score;
}
else
printf("nota invalida\n");
}
printf("media = %.2f\n",sum/2);

}
}
return 0;
}
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Replies
Unknown5 April 2020 at 14:57
//Shazzed Hossain Shajal
#include
int main()
{
double x,y,av,n;
while(1)
{
scanf("%lf",&x);
if(x<0 || x>10)
{
printf("nota invalida\n");
continue;
}
while(1)
{
scanf("%lf",&y);
if(y<0 || y>10)
{
printf("nota invalida\n");
continue;
}
break;
}
av=(x+y)/2.0;
printf("media = %.2f\n",av);
printf("novo calculo (1-sim 2-nao)\n");
while(1)
{
scanf("%lf",&n);
if(n!=1 && n!=2)
{
printf("novo calculo (1-sim 2-nao)\n");
continue;
}
break;
}
if(n==2)
{
break;
}
}
}
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Replies
Rafael Correia8 August 2020 at 01:47
This comment has been removed by the author.
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Rafael Correia8 August 2020 at 01:52

class Program
{
static void Main(string[] args)
{

{
bool a, b; double soma = 0.0, media = 0.0, n1, n2; int x;

do
{

do
{
n1 = double.Parse(Console.ReadLine(), CultureInfo.InvariantCulture);
if (n1 > 0.0 && n1 <= 10.0)
{
a = true;
soma = n1;
}
else
{
a = false;
Console.WriteLine("nota invalida");
}
} while (a == false);

do
{
n2 = double.Parse(Console.ReadLine(), CultureInfo.InvariantCulture);
if (n2 > 0.0 && n2 <= 10.0)
{
b = true;
soma = n1 + n2;
}
else
{
b = false;
Console.WriteLine("nota invalida");
}
} while (b == false);

media = soma / 2.0;
Console.WriteLine("media = " + media.ToString("F2", CultureInfo.InvariantCulture));

do
{
Console.WriteLine("novo calculo (1-sim 2-nao)");
x = int.Parse(Console.ReadLine());
} while (x < 1 || x > 2);

} while (x != 2 || x == 1);
}

}
}

eu encadeei alguns "do" pra dar certo em C#.
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Replies
Kamran17 August 2020 at 22:30
Repeat teke boji nai vai, i don’t understand from repeat, please describ?
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Unknown26 October 2020 at 13:32
Isn't it is the easiest way to solve in C.
#include

int main()
{
double a,b=0,c=0,s=0;
int x;
while(scanf("%lf",&a))
{
if(a>=0&&a<=10)
{
b++;
s+=a;
}
else printf("nota invalida\n");
if(b==2)
{
printf("media = %.2lf\n",s/2);
s=0;
printf("novo calculo (1-sim 2-nao)\n");
while(scanf("%d",&x))
{
if(x==1)
{
b=0;
break;
}
else if(x==2)
{
c=x;
break;
}
else printf("novo calculo (1-sim 2-nao)\n");
}
if(c==2) break;
}
}
return 0;
}//end of line
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