Sunday, 27 March 2016

Solution of URI 1142 :: PUM

   , ,  5 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int N, a,b,c=1,d=4;
    scanf("%d", &N);
    for(a=1;a<=N;a++)
    {
        for(b=c;b<=d;b++)
        {
            if(b%4==0)
                printf("PUM\n");
            else
                printf ("%d ",b);
        }
        c+=4; d+=4;
    }
    return 0;
}

5 comments:

  1. Earnus28 May 2017 at 06:20

    why c+=4; d+=4; ?

    ReplyDelete
  2. Unknown7 March 2019 at 23:33

    #include
    int main()
    {
    int n,i,a=0;
    scanf("%d",&n);

    for(i=1; i<n*4; i++)
    {
    printf("%d ",i);
    a++;
    if(a==3)
    {
    printf("PUM\n");
    a=0;
    i=i+1;
    }
    }

    return 0;
    }

    ReplyDelete
  3. Liquid Modernity Tastes Like Urine6 April 2019 at 03:29

    Using while

    #include

    int main()
    {
    int N, a, b, c, d;

    scanf("%d", &N);

    a = 0;
    b = 1;
    c = 2;
    d = 3;


    while(a < N)
    {
    printf("%d %d %d PUM\n", b, c, d);
    a++;
    b = b + 4;
    c = c + 4;
    d = d + 4;
    }

    return 0;

    }

    ReplyDelete
  4. Faisal Mahmud4 May 2019 at 19:18

    #include
    int main()
    {
    int n,i,j,x=1,y=3;
    scanf("%d",&n);

    for(i=1;i<=n;i++)
    {
    for(j=x;j<=y;j++)
    {
    printf("%d ",j);
    }
    printf("PUM\n");
    x+=4;
    y+=3;
    }
    return 0;
    }

    ReplyDelete
  5. Anonymous1 April 2020 at 21:41

    #include
    int main()
    {
    int n,i,j,k=1;

    scanf("%d",&n);

    for(i=1;i<=n;i++)
    {
    printf("%d %d %d PUM\n",k,k+1,k+2);
    k=k+4;

    }


    return 0;
    }

    ReplyDelete

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