Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
int main()
{
int a,b=0;
double c,d=0;
while(1)
{
scanf("%d", &a);
if(a<0)
break;
else
{
b+=a;
d++;
}
}
c=b/d;
printf("%.2lf\n",c);
return 0;
}
here, what's the use of 'b'?
ReplyDeleteb will calculate the total sum.
ReplyDeleteWhat if d was an int instead of being double?
ReplyDelete#include
ReplyDeleteint main()
{
float n,a,sum=0;
int count=0;
scanf("%f",&n);
while(n>=0)
{
count++;
sum+=n;
scanf("%f",&n);
}
a=sum/(float)count;
printf("%.2f\n",a);
return 0;
}
reply....