Friday, 15 April 2016

Solution of URI 1179 :: Array Fill IV

   , ,  3 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int a,b,c=0,d,e,f,g,h,i,j,l=0,m=0,x=0,n,p,par[5],impar[5],ara[15];
    for(b=0; b<15; b++)
        scanf("%d", &ara[b]);
    for(a=0; a<15; a++)
    {
        if(l==5)
        {
            for(n=0; n<5; n++)
                printf("impar[%d] = %d\n", n, impar[n]);
            l=0;
        }
        if(m==5)
        {
            for(p=0; p<5; p++)
                printf("par[%d] = %d\n", p, par[p]);
            m=0;
        }

        if(ara[a]%2!=0)
        {
            impar[c]=ara[a];
            ++c;
            l++;
            if(c==5) c=0;
        }
        if(ara[a]%2==0)
        {
            par[x]=ara[a];
            ++x;
            m++;
            if(x==5) x=0;
        }
    }
    for(i=0; i<l; i++)
            printf("impar[%d] = %d\n", i, impar[i]);
    for(j=0; j<m; j++)
            printf("par[%d] = %d\n", j, par[j]);
    return 0;
}

3 comments:

  1. Ahmed9 July 2018 at 18:12

    thank you for your perfect solution

    ReplyDelete
  2. Unknown25 August 2019 at 02:30

    #include
    int main()
    {
    int par[5],impar[5],i,j=0,k=0,a,m;
    for(i=1; i<16; i++)
    {
    scanf("%d",&a);
    if(a%2==0)
    {
    par[j++]=a;
    if(j==5)
    {
    for(m=0; m<5; m++)
    printf("par[%d] = %d\n",m,par[m]);
    j=0;
    }
    }
    else
    {
    impar[k++]=a;
    if(k==5)
    {
    for(m=0; m<5; m++)
    printf("impar[%d] = %d\n",m,impar[m]);
    k=0;
    }
    }
    }
    for(i=0;i<k;i++)printf("impar[%d] = %d\n",i,impar[i]);
    for(i=0;i<j;i++)printf("par[%d] = %d\n",i,par[i]);
    return 0;
    }

    ReplyDelete
  3. Unknown17 December 2019 at 09:36

    #include
    int main()
    {
    int n[10],n2[10],n3[5],n4[5],i,e=0,o=0,e2=0,o2=0,a[15];
    for(i=0;i<15;i++)
    {
    scanf("%d", &a[i]);
    if(i<=9)
    {
    if(a[i]%2==0)
    {
    n[e]=a[i];
    e++;
    }
    else
    {
    n2[o]=a[i];
    o++;
    }
    }
    else
    {
    if(a[i]%2==0)
    {
    n3[e2]=a[i];
    e2++;
    }
    else
    {
    n4[o2]=a[i];
    o2++;
    }
    }
    }
    for(int j=0;j<e;j++)
    {
    printf("par[%d] = %d\n", j,n[j]);
    }
    for(int j=0;j<o;j++)
    {
    printf("impar[%d] = %d\n", j,n2[j]);
    }
    for(i=0;i<o2;i++)
    {
    printf("impar[%d] = %d\n", i,n4[i]);
    }
    for(i=0;i<e2;i++)
    {
    printf("par[%d] = %d\n", i,n3[i]);
    }
    }

    ReplyDelete

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