Solution of URI 1189 :: Left Area

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/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    double a=0.0, M[12][12];
    char T[2];
    int C,x,y,z,p=0,r=4;
    scanf("%s", &T);
    for(x=0;x<=11;x++)
    {
        for(y=0; y<=11; y++)
            scanf("%lf", &M[x][y]);
    }
    for(z=1; z<=10;z++)
    {
        if(z<=5)
        {
            for(C=0; C<=p;C++)
                a+=M[z][C];
            p++;
        }
        else if(z>=6)
        {
        for(C=0; C<=r; C++)
            a+=M[z][C];
        r--;
        }
    }
    if(T[0]=='S')
        printf("%.1lf\n",a);
    else if(T[0]=='M')
    {
        a=a/30.0;
        printf("%.1lf\n",a);
    }
    return 0;
}