Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/
#include <stdio.h>
int main()
{
double n, ans1, ans2;
scanf("%lf", &n);
ans1 = n/log(n);
ans2 = (1.25506)*(n/log(n));
printf("%.1lf %.1lf\n", ans1, ans2);
return 0;
}
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