Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.
/**Bismillahir Rahmanir Rahim.**/ #include <stdio.h> int main() { double n, ans1, ans2; scanf("%lf", &n); ans1 = n/log(n); ans2 = (1.25506)*(n/log(n)); printf("%.1lf %.1lf\n", ans1, ans2); return 0; }
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