Tuesday, 30 August 2016

Solution of URI 2164 :: Fast Fibonacci


Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>

int main()
{
    double n, x, y, ans;
    scanf("%lf", &n);
    x = (1 + sqrt(5))/2.0;
    y = (1 - sqrt(5))/2.0;
    ans = (pow(x,n) - pow(y,n))/sqrt(5);
    printf("%.1lf\n", ans);
    return 0;
}

0 comments:

Post a Comment

Note: only a member of this blog may post a comment.