Sunday, 27 March 2016

Solution of URI 1144 :: Logical Sequence

   , ,  3 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int a,b,c,d,e,f;
    scanf("%d", &a);
    for(b=1; b<=a; b++)
    {
        c=b*b;
        d=b*b*b;
        printf("%d %d %d\n",b,c,d);
        e=c+1;
        f=d+1;
        printf("%d %d %d\n",b,e,f);
    }
    return 0;
}

3 comments:

  1. Unknown16 February 2017 at 03:21

    Hi, my code is giving 'Presentation Error' and I can't figure out why. Can you help me?
    """
    a=0
    N=int(input())
    if 1<N<1000:
    for i in range(1,N+1):
    for k in range(1,4):
    print(i**k,end=' ')
    print()

    for j in range(1,4):
    if j==2 or j==3:
    a=i**j+1
    print(a, end=' ')
    else:
    print(i**j,end=' ')
    a=0
    print()
    """

    ReplyDelete
  2. Unknown22 March 2017 at 23:05

    #include
    int main()
    {
    int N,q,r,i;
    scanf("%d", &N);
    for(i=1;i<=N;i++)
    {
    q=i*i;
    r=i*i*i;
    printf("%d %d %d\n",i,q,r);
    printf("%d %d %d\n",i,q+1,r+1);
    }
    return 0;
    }

    ReplyDelete
  3. Faisal Mahmud4 May 2019 at 20:29

    #include
    int main()
    {
    int n,i;
    scanf("%d",&n);
    for(i=1;i<=n;i++)
    {
    printf("%d %d %d\n",i,i*i,i*i*i);
    printf("%d %d %d\n",i,(i*i)+1,(i*i*i)+1);
    }
    return 0;
    }

    ReplyDelete

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