Sunday, 27 March 2016

Solution of URI 1145 :: Logical Sequence 2

   , ,  18 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    int X,Y,z,a,b=0;
    scanf("%d%d", &X,&Y);
    for(a=1; a<=Y; a++)
    {
        b++;
        if(b==X) printf("%d",a);
        else printf("%d ", a);
        if(b==X)
        {
            b=0;
            printf("\n");
        }
    }
    return 0;
}

18 comments:

  1. Earnus28 May 2017 at 20:14

    if(b==X)
    printf("%d",a);
    else printf("%d ", a);
    if(b==X)
    {
    b=0;
    printf("\n");
    }
    Can I use same conditions ? Like u use if(a==x) twice.

    ReplyDelete
  2. Unknown6 July 2018 at 00:40

    man your code is readless

    ReplyDelete
  3. Bushra15 August 2018 at 02:02

    I has been tried to solve this problem . But always seems the presentation error . #include
    int main()
    {
    int i,n,a,b=0;
    scanf("%d %d",&a,&n);

    for(i=1; i<=n; i++)
    {
    printf("%d ", i);
    b++;
    if(b==a)
    {
    printf("\n");
    b=0;
    }
    }

    return 0;
    }
    l


    whats the problem

    ReplyDelete
  4. Unknown22 September 2018 at 19:48

    WHY presentation error !

    ReplyDelete
  5. Unknown8 December 2018 at 20:01

    #include
    int main()
    {
    int X,Y,j,i;
    scanf("%d%d", &X,&Y);
    if(Y>X)
    for(i=1;i<=Y;i=i+X)
    {
    for(j=i;j<X+i;j++)
    {
    printf("%d ", j);
    }
    printf("\n");
    }
    return 0;
    }




    PRESENTATION ERROR WHY? please,,,,

    ReplyDelete
  6. Fabio Clementino31 March 2019 at 00:29

    This comment has been removed by the author.

    ReplyDelete
  7. Faisal Mahmud4 May 2019 at 21:27

    #include
    int main()
    {
    int x,y,i,j=0;
    scanf("%d %d",&x,&y);

    for(i=1;i<=y;i++)
    {
    printf("%d",i);
    j++;
    if(j<x)
    printf(" ");
    else
    {
    printf("\n");
    j=0;
    }
    }
    return 0;
    }

    ReplyDelete
  8. Nishan16 September 2019 at 18:59

    #include
    using namespace std;
    main(){
    int x,y,i,j,a;
    cin >> x;
    cin >> y;

    if((x>1 && x<20) && (y>x) && y<100000){
    for(i=1;i<=y;i++){
    a=i;
    for(j=1;j<=x;j++){
    if(a==y){
    cout << a << " ";
    a++;
    break;
    }
    else{
    cout << a << " " ;
    a++;
    }
    }
    cout << endl;
    i+=x-1;
    }
    }
    }

    why presentation error

    ReplyDelete
  9. Morse14 November 2019 at 04:52

    #include
    void main(void){
    int x, y, cont;
    scanf("%i", &x);
    do{
    scanf("%i", &y);
    }while(y <= x);
    for (cont = 1;cont <= y; cont++){
    if (cont % x == 0 || cont == y){
    printf("%i\n", cont);
    }
    else{
    printf("%i ", cont);
    }
    }
    }

    ReplyDelete
  10. mued5 February 2020 at 21:24

    This comment has been removed by the author.

    ReplyDelete
  11. Unknown3 March 2020 at 13:38

    #include
    int main ()
    {
    int n,a,h;

    scanf ("%d%d",&a,&h);
    for (n=1;n<=h;n++)
    {
    if (n%a==0)
    {
    printf ("%d \n",n);
    }
    else
    {
    printf ("%d ",n);}

    }
    return 0;
    }

    ReplyDelete
  12. Venom30 March 2020 at 03:05

    What is the problem in this code can anyone help me

    #include

    int main()
    {

    int i, x, y, j, c = 1;

    scanf("%d %d", &x, &y);

    for (i = 1; i <= y; i++)
    {

    for (j = 1; j <= x; j++)
    {

    if (c == y + 1)
    {
    break;
    }
    if (c == x)
    {
    printf("%d", c++);
    }
    else
    {
    printf("%d ", c++);
    }
    }


    printf("\n");

    if (c == y + 1)
    {
    break;
    }
    }
    }

    ReplyDelete
  13. Mahadi Hasan26 April 2020 at 13:03

    # include

    int main ()
    {
    int x,y;
    scanf("%d%d", &x,&y);
    int i;
    for (i=1; i<=y; i++)
    {
    if((i%x)==0)
    {
    printf("%d\n", i);
    }
    else
    {
    printf("%d ",i);
    }
    }

    return 0;
    }

    ReplyDelete
  14. Unknown22 July 2020 at 11:14

    #include
    #include

    int main()
    {
    int i, s, j, k, temp=0;
    scanf("%d %d", &s, &j);
    for(i=1; i<=j; i++)
    {
    printf("%d ",i);
    temp+=1;
    if(temp%s==0)
    {
    printf("\n");
    }
    }

    return 0;
    }

    ReplyDelete
  15. Unknown22 July 2020 at 11:21

    why I'm getting presentation error?

    ReplyDelete
  16. Kamran23 August 2020 at 19:59

    #include

    int main()
    {
    int x, y, i, j, n, m;
    scanf("%d%d",&x,&y);
    for(i=1;i<=y;i++)
    {
    if(i%x==0)
    {
    printf("%d\n",i);

    }
    else
    {
    printf("%d ",i);
    }
    }

    return 0;
    }

    ReplyDelete
  17. Kamran23 August 2020 at 20:00

    very simple

    ReplyDelete
  18. mahmoud18 November 2020 at 14:56

    #include
    using namespace std;
    int main() {
    int x, y;
    cin >> x >> y;
    for (int i = 1; i <= y; i++) {
    cout << i << " ";
    if (i % x == 0)
    cout << endl;

    }
    }
    i got presention error

    ReplyDelete

Note: only a member of this blog may post a comment.