Saturday, 30 April 2016

Solution of URI 1184 :: Below the Main Diagonal

   , ,  2 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    double a=0.0, M[12][12];
    char T[2];
    int C,x,y,z,p=0;
    scanf("%s", &T);
    for(x=0;x<=11;x++)
    {
        for(y=0; y<=11; y++)
            scanf("%lf", &M[x][y]);
    }
    for(z=1; z<=11;z++)
    {
        for(C=0; C<=p;C++)
            a+=M[z][C];
        p++;
    }
    if(T[0]=='S')
        printf("%.1lf\n",a);
    else if(T[0]=='M')
    {
        a=a/66.0;
        printf("%.1lf\n",a);
    }
    return 0;
}

2 comments:

  1. MH Adnan28 March 2019 at 01:30

    This comment has been removed by the author.

    ReplyDelete
  2. Unknown6 August 2020 at 00:09

    #include
    int main()
    {
    int i , j,p=0 ;
    double N[i][j], sum =0.0 ;
    char c[2];
    scanf ("%s",&c);
    for(i=0;i<12;i++)
    {
    for(j=0;j<12;j++)
    {
    scanf ("%lf",&N[i][j]);
    if (i>j)
    {
    sum=sum+N[i][j];
    }
    }
    }
    if (c[0]=='S')
    {
    printf ("%.1lf\n",sum);
    }
    else if (c[0]=='M')
    {
    printf ("%.1lf\n",sum/66.0);
    }
    return 0;
    }




    why runtime error

    ReplyDelete

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