Saturday, 30 April 2016

Solution of URI 1185 :: Above the Secundary Diagonal

   , ,  2 comments

Before seeing the solution make sure that you tried enough. Don’t paste the whole code, just find out the logic. If you stuck in trouble, just inform me on comment.

/**Bismillahir Rahmanir Rahim.**/

#include <stdio.h>
int main()
{
    double a=0.0, M[12][12];
    char T[2];
    int C,x,y,z,p=10;
    scanf("%s", &T);
    for(x=0;x<=11;x++)
    {
        for(y=0; y<=11; y++)
        scanf("%lf", &M[x][y]);
    }
    for(z=0; z<=10;z++)
    {
        for(C=0; C<=p;C++)
            a+=M[z][C];
        p--;
    }
    if(T[0]=='S')
        printf("%.1lf\n",a);
    else if(T[0]=='M')
    {
        a=a/66.0;
        printf("%.1lf\n",a);
    }
    return 0;
}

2 comments:

  1. Unknown21 October 2018 at 19:50

    #include
    int main()
    {

    int i,j,b=11;
    float a[12][12],s=0.0,m=0.0,x=0.0;
    char c;
    scanf("%c",&c);
    for(i=0;i<=11;i++)
    {
    for(j=0;j<=11;j++)
    {
    scanf("%f",&a[i][j]);
    if(j<b && i!=11){
    s=s+a[i][j];
    m++;
    }
    }
    b--;
    }
    if(c=='S'){
    printf("%.1f\n",s);
    }
    else if(c=='M')
    {
    x=s/m;
    printf("%.1f\n",x);
    }
    return 0;
    }

    ReplyDelete
  2. Unknown21 October 2018 at 19:50

    #include
    int main()
    {

    int i,j,b=11;
    float a[12][12],s=0.0,m=0.0,x=0.0;
    char c;
    scanf("%c",&c);
    for(i=0;i<=11;i++)
    {
    for(j=0;j<=11;j++)
    {
    scanf("%f",&a[i][j]);
    if(j<b && i!=11){
    s=s+a[i][j];
    m++;
    }
    }
    b--;
    }
    if(c=='S'){
    printf("%.1f\n",s);
    }
    else if(c=='M')
    {
    x=s/m;
    printf("%.1f\n",x);
    }
    return 0;
    }

    ReplyDelete

Note: only a member of this blog may post a comment.